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-
- TESTDISK
-
- THE NEXT GENERATION OF DISK THROUGHPUT BENCHMARKS
-
-
- (c) COPYRIGHT 1988-1989 BY
- COLUMBIA DATA PRODUCTS, INC.
- 1070B RAINER DRIVE
- P.O. BOX 2584
- ALTAMONTE SPRINGS, FL 32714-2584
- (407) 869-6700
-
- Welcome to the world of hard disk performance measurement! Until
- recently, measuring performance of disk subsystems for the IBM
- PC/XT/AT/PS2 and compatibles has been somewhat over simplified by
- the industry. Now, with the introduction of SST-equipped
- controllers, contemporary benchmarks are no longer adequate to
- predict disk subsystem performance in actual everyday use.
- Benchmarks for the next generation of mass storage systems for
- the IBM PC/XT/AT/PS2 and compatibles now require that more
- variables be taken into account to accurately measure the
- throughput a system can achieve.
-
- ACCESS TIMES
-
- Until now the only major variable that generally was considered
- was the Average Disk Head Seek Time, expressed in milliseconds
- (commonly referred to as Average Access Time). From the
- standpoint of a disk drive manufacturer, this is the major item
- which is used to market their products and they are consistently
- touting faster and faster access times. But the REALLY important
- aspects of overall disk system performance are just not shown.
-
- Let's take a disk that has an access time of 20 milliseconds, for
- example. Does that mean that just because it has a 20
- millisecond access time that it is fast? Well, yes and no. It
- means that it can move the disk head from one spot on the disk to
- another spot on the disk in an overall average of 20
- milliseconds. As far as access times go, a 20 millisecond
- average access time disk drive is relatively fast. But it tells
- you nothing of how fast it will deliver data to your computer.
- So you ask, "Well, then, how can I tell when a disk drive is
- fast?" Read on!!
-
- Disk performance really starts at your hard disk controller--not
- at your disk. Disk performance is a function of how rapidly data
- can be transferred from the hard disk into your computer. If you
- have a disk controller which can move data at 29,000 characters
- per second (which is not uncommon), then it stands to reason that
- it will take you six seconds to load your 174,000 character
- spreadsheet. So, whether you have a 20 millisecond hard disk or a
- 65 millisecond hard disk, it still takes six seconds to recover
- your spreadsheet!!
-
- DATA RATES
-
- As you can probably tell, disk performance measurement, which
- tells you how long you are going to wait for something to load
- into your computer from your hard disk, can best be expressed in
- characters per second. Since one character is equal to one byte,
- and most disk systems move data in thousands of bytes (or
- characters) per second, the standard term for data rate is
- kilobytes (1024 bytes) per second (KBS).
-
- Some benchmark tests actually DO report the data transfer rate
- (in KBS) of the controller. They measure the movement of data
- from the disk to memory. They only report, however, the highest
- data rate your disk drive can achieve on your computer. Now, if
- you read closely, you will notice that I said the HIGHEST data
- rate your disk drive can achieve on your computer. Does this
- mean that there is more than one data rate expressed in KBS which
- can be achieved by your disk system? The answer is YES!
-
- WHICH DATA RATES?
-
- Whenever the disk system is asked to move data from the hard
- drive into memory or vice versa, it takes time for the disk
- system to figure out what you are asking for, where it is on the
- disk, and how to move the data. This time lag is called command
- processing latency. It is this initial time lag before data is
- actually moved to or from the disk that is the evil of disk
- performance. Since this time lag is pretty much a constant, it
- is wise to get as much data off of the disk at one time rather
- then to repeatedly ask for data in small blocks. For example, if
- you wanted to move 327,680 bytes off the disk and the initial
- command processing latency was 70 milliseconds (70/1000 of a
- second) and the 327,680 bytes was moved in 512 byte blocks, you
- would be asking the disk to move data 640 times and your command
- processing latency alone would be 44.8 seconds (640 X .070
- seconds)!!
-
- If, however, you moved the 327,680 bytes off the disk 65,536
- bytes (64 KB) at a time, you would be asking the disk to move
- data only 5 times and your command processing latency would be
- 35/100's of a second (5 X .070 seconds). That is 992% faster!!!
- 44.8 seconds compared to a fraction of a second and that's not
- even counting the time to move the data!! This is extremely eye
- opening isn't it?
-
- So, you see, it doesn't appear to be very wise to ask the disk
- for data in small blocks, now does it? But this is precisely the
- way most application programs (such as Lotus, Dbase, etc) DO move
- their data--512 bytes at a time. Now, these other disk
- performance testers I mentioned, test the disk by moving data
- 65,536 bytes at a time. So, you have absolutely no idea how fast
- Lotus, Dbase, or any of the other application programs can
- retrieve data. All you know, is that IF YOUR PROGRAM MOVED DATA
- 64K AT A TIME OFF THE DISK, THIS IS HOW FAST IT WOULD BE!! In
- essence, then, to measure disk performance in 64K blocks is
- utterly useless to you if you really want to know how fast your
- application program can load data.
-
- Your Columbia Data Products disk performance tester, TESTDISK,
- doesn't just move data off the disk in 64K blocks. It moves the
- data in 8 different size blocks: 1/2K, 1K, 2K, 4K, 8k, 16K, 32K
- and 64K. This will give you a clear idea of how fast your disk
- system really is. When you run this on a disk system which is
- 650 KBS at 64K blocks, you may be surprised to find that it is
- only 120 KBS (or less) at the 1/2K block rate. You may even find
- that you paid a premium for a "fast" disk system and you never
- will see the "speed" because the programs you run cannot utilize
- it.
-
- One last word about average access times. They are important.
- We at Columbia Data Products do not dispute that. They account
- for a sizeable portion of your command processing latency. You
- should not, however, pay a premium for a "fast" access time if
- you can't take advantage of it. This test will help you
- determine that. The last example I wish to give will compare two
- hard drives. The first hard drive has a 1 millisecond average
- access time and the other has a 100 millisecond average access
- time. The 1 millisecond access time hard drive can move data off
- itself and into the computer at 100 thousand bytes per second
- (100 KBS). The 100 millisecond access time hard drive can move
- data off itself and into the computer at 900 thousand bytes per
- second (900 KBS).
-
- To move 900 thousand bytes, the 1 millisecond access time hard
- drive takes 9 seconds while the 100 millisecond access time hard
- drive takes only 1 second. Therefore, the 100 millisecond access
- time hard drive is 9 times faster moving data even though it is
- 100 times slower moving its head! It probably costs a lot less,
- too. I think you are beginning to see the picture.
-
- RUNNING TESTDISK
-
- NOTE: TESTDISK WILL NOT RUN WITH DOS VERSIONS 3.31 OR GREATER.
- THE I/O INTERFACE THAT TESTDISK USES TO MEASURE DISK PERFORMANCE
- HAS BEEN CHANGED WITH THESE DOS VERSIONS. A FUTURE RELEASE OF
- TESTDISK WILL WORK WITH THESE DOS VERSIONS.
-
- To start testdisk, simply type TESTDISK and press enter. First,
- you must choose whether or not you want to run testdisk in color.
- Next, you will be asked whether or not your printer can print the
- two characters which are displayed on the screen. A printer
- which can print the IBM character set will have no trouble
- printing the displayed characters. The printer will print out a
- graph of the test results, if you desire, at the completion of
- the test.
-
- You will then be asked for a DOS drive letter (C:, D: etc) to
- test. Next you will be asked how much data in Kilobytes you
- would like to read. We recommend a minimum of at least 1000K for
- an accurate test. The test then proceeds to perform a
- verification pass to insure that the area being tested is
- error-free. If it is not, an error will occur and the test will
- stop. If it is error-free, the test will continue.
-
- The data is then read by two methods--SEQUENTIAL and REPETITIVE.
- The SEQUENTIAL test will read data from the drive the same way
- that your application program will. The REPETITIVE test, which
- reads data the way most "disk test" programs do, will not reflect
- real world performance. We have included the REPETITIVE test for
- comparitive purposes only.
-
- TESTDISK creates a graph of 16 individual tests, 8 SEQUENTIAL,
- and 8 REPETITIVE. Each individual test reads data in only one
- block size. The tests are run in pairs (one SEQUENTIAL and one
- REPETITIVE) for block sizes of 1/2K, 1K, 2K, 4K, 8K, 16K, 32K and
- 64K. In other words, if you are reading 1000K in 1/2K blocks,
- you will access the disk drive 2000 times for each individual
- test. For the 1K test, you will access the disk 1000 times, then
- 500 times for the 2K test, 250 times for the 4K test, and so on.
-
- The SEQUENTIAL test reads the disk one sector after another,
- beginning with data in sector 1 on the hard drive. To read data
- sequentially, the hard drive head reads all the sectors on the
- first track, then is moved from that track to the next track, and
- so on, until the amount of data requested is read. The first
- sequential test shows the rate for reading the requested amount
- of data in 1/2K blocks, starting in sector 1. The second test
- also begins in sector 1 and reads in 1K blocks, the third begins
- once again in sector 1 and reads in 2K blocks, and so on.
-
- The REPETITIVE read test is included to show how most other disk
- test programs read their data--repetitively, 64K at a time.
- Rather than reading the data sequentially, as required by most
- application programs, data from the same spot on the disk is
- repeatedly read over and over in 64K blocks. Reading the same
- data repeatedly and in such large blocks does not accurately test
- disk performance for an application program. Our first
- repetitive test represents the requested amount of data being
- read from one spot on the disk in 1/2K blocks, the second test
- shows the rate for reading the same data from the same spot in 1K
- blocks, and so on, up to 64K.
-
- As you may have noticed, when running TESTDISK there is a lot of
- descriptive text that is printed to the screen to inform you of
- what is happening. After running the test a few times all this
- descriptive text may become a bit annoying. This is why we have
- included the ability to turn all the descriptive text off. Simply
- type TESTDISK /I when loading TESTDISK and the descriptive text
- will not appear.
-
- IN SUMMARY
-
- The sequential test results will indicate your disk performance
- on user programs which call for data from the disk. Use of the
- repetitive test will show only what other test programs show.
-
-
- HAPPY TESTING!!